How Much Power Does a Hydraulic Pump Need?

The pump is a simple device that transfers energy from one place to another as it rotates an impeller. It could be powered by wind, water, or even the vacuum created inside of your home. To answer this question you will need to know how much power it needs and some basic information about hydraulic pumps in general.

The “hydraulic pump selection” is a question that has been asked for years. The answer to the question is most likely going to be different depending on what type of hydraulic pump you are looking for and what your needs are.

The operating pressure of the system must be determined in order to acquire the proper flow and guarantee that you have a suitable pump. The function of a hydraulic pump is to provide enough power to push a structure’s operating pressure high enough to transfer hydraulic fluid at the proper pump flow rate. Let’s look at How Much Power Does a Hydraulic Pump Require.

What Kind of Power Does a Hydraulic Pump Require?

How Much Power Does a Hydraulic Pump Need

It generates enough power to counterbalance the load-induced pressure at the pump output. When a hydraulic pump is switched on, it creates a vacuum at the pump inlet, which draws liquid from the storage into the intake line of the pump and physically transfers it to the pump output, pushing it into the hydraulic system.

Pumps and their Power Uses

A rotary vane 380v hydraulic power pack pump is a positive-displacement pump with vanes connected to a rotor rotating within a chamber. In certain cases, the length and tension of these vanes may be adjusted to maintain them in contact with the pump’s walls while it rotates. Vane pump design is influenced by how the vanes are pressed into contact with the pump housing and how the vane tips are machined.

Gear pumps (fixed displacement) with external teeth are simple and cost-effective. Hydraulic gear pumps will have a swept volume or displacement of 1 to 200 milliliters. They are the least efficient of the three basic pump types (gear, vane, and piston pumps) in terms of volumetric efficiency.

The meshing of the gear teeth creates pressure by driving fluid around the gears and pressurizing the exit. The main objective is to create a tight seal between the interior of the housing and the vane while avoiding metal-to-metal contact. The vane is forced out of the rotating center and towards the pump housing by spring-loaded vanes.

Screw pumps (fixed displacement) consist of two Archimedes’ screws that are intertwined and housed in the same chamber. These pumps are designed to handle high flows while maintaining low pressure. They were used to control ball valves on ships having a constant pressure hydraulic system that ran the length of the ship. The hydraulic reaction force is communicated in an axially opposite direction to the flow direction, which is the fundamental concern with screw pumps.

The most common motor used to power a hydraulic pump is a three-phase, induction-type Design B motor. When operated in a normal temperature setting, most open frame sizes have a service factor of 0.15, which means that the motor may be overloaded by roughly 15% of the current specified on its nameplate. TEFC and explosion-resistant motors have a service factor of 1.0. If the average horsepower is less than the nameplate rating + service factor when applicable, an electric motor might be overloaded for short intervals throughout the cycle. The user may choose how much intermittent overloading he or she wants. However, we suggest that the overload be no more than 25% higher than the nameplate current rating and last no more than 10% of the time required to complete the cycle.

Variables Required for Power Calculation 

This is determined by dividing the theoretical flow by the actual flow delivered by the pump at a given pressure. The theoretical flow is calculated by multiplying a hydraulic pump’s displacement per revolution by its drive speed.

For example, if a hydraulic pump has a 100cc/rev displacement and runs at 1000 RPM, the maximum flow is 100 liters/minute.

  • Mechanical/Hydraulic System Efficiency

By dividing the theoretical torque required to drive it by the actual torque required to drive it, the mechanical/hydraulic efficiency is computed. No force or torque would be required to drive the pump if it provided flow at zero pressure. We instinctively understand that owing to mechanical and fluid friction, this is not feasible.

The mechanical/hydraulic efficiency of a pump is calculated by multiplying the theoretical torque needed by the actual torque required.

The driving power is calculated using overall efficiency at a particular flow and pressure. This is used to figure out how much driving power a hydraulic pump needs at a given pump flow and pressure. To give the dealer’s result, both measurements must be obtained first. These criteria should, in theory, determine the hydraulic power necessary to drive a pump: The product of volumetric and mechanical/hydraulic efficiency is overall efficiency. The following is a list of resources –  

  • The mass flow rate
  • a liquid’s density
  • Difference in height


The kind of pump is the most important consideration for anybody running a pump. Following that, students may enter variables into the formulae below and compute. To determine the ultimate power, the volume and mechanical effectiveness must be computed.

Watch This Video-

A hydraulic pump is a device that uses mechanical power from a motor to create pressure. Electric motors are able to provide enough power for hydraulic pumps. The “5hp electric motor with hydraulic pump” will work well for this application.

Frequently Asked Questions

How do you calculate the power needed for a hydraulic pump?

A: The hydraulic pump power is determined by the head or impeller size, the flow rate of water and speed.

How do you size a hydraulic motor and pump?

A: The most common way to size a hydraulic motor and pump is with the equation Hp = Volts x Amps.

How do you size a hydraulic pump?

A: I am a hydraulic pump. If you ask me how size, I will tell you that it depends on the type of hydraulic pump and what scale or if are using in engineering because there is alot to consider when sizing one. One thing worth noting though is that as long as the input pressure does not exceed about 50 psi, then any flow rate up to about 1 liters per minute can be used for most designs available today.

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